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A pendulum is hung in a very high buildi...

A pendulum is hung in a very high building and is moving freely to and fro like a simple harmonic oscillator. If the acceleration of the bob is `16 ms^(-1)` at a distance of 4 m from the mean position, then the time period is

A

2s

B

1s

C

`2pis`

D

`pis`

Text Solution

Verified by Experts

The correct Answer is:
D

Acceleration, `a=16m//s^(2)`
displacement, `y=4m`
According to SHM,
`a=omega^(2)y`
`omega^(2)=(16)/(4)=4`
`therefore omega=2rad//s`
Time period, `T=(2pi)/(omega)=(2pi)/(2)`
`T=pisec`
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