The path difference between the two waves `y_(1) = a_(1) sin (omega t - (2pi x)/(lambda))` and `y_(2) = a_(2) cos (omega t - (2pi x)/(lambda) + phi)` is ……….

Options

A. `(lambda)/(2pi)"" phi`
B. `(lambda)/(2pi) ( phi + (pi)/(2))`
C. `(2pi)/(lambda) (phi + (pi)/(2))`
D. `(2pi)/(lambda) "" phi`

Answer

B

Explanation

Phase difference = `phi + (pi)/(2)` , Path difference = `(lambda)/(2) (phi + (pi)/(2))`