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A source of sound and a listener are app...

A source of sound and a listener are approaching each other with a speed of `40ms^(-1)` The apparent frequency of a note produced by the source is 400 Hz. Then its true frequency is (velocity of sound in air = `360 ms^(-1)` )

A

320 Hz

B

400 Hz

C

360 Hz

D

420 Hz

Text Solution

Verified by Experts

The correct Answer is:
A
`f. = ((v + v_(0))/(v - v_(s))) f implies 400 = [(360 + 40)/(360 - 40)] f implies f = 320` Hz
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