A transverse wave propagating on a stretched string of linear density `3 xx 10^(-4) kg m^(-1)` is represented by the equation `y = 0.2 sin (1.5 x + 60 t)`
Where x is in metres and t is in seconds . The tension in the string (in newtons) is :

Options

A. 0.24
B. 0.48
C. `1.20`
D. `1.80`

Answer

A

Explanation

`v = sqrt((T)/(m)) = (omega)/(k) implies T = ((omega)/(k))^(2) m = ((60)/(1.5))^(2) xx 3 xx 10^(-4) = 0.48` N