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A light string passing over a smooth lig...

A light string passing over a smooth light pulley connects two blocks of masses `m_1` and `m_2` (vertically). If the acceleration of the system is g/8 then the ratio of the masses is

A

`8:1`

B

`9:7`

C

`4:3`

D

`5:3`

Text Solution

Verified by Experts

The correct Answer is:
B
The FBD diagram, the force can be
` m_2a = T -m_2 g " " [ a = g/8]`
`m_1 a = m_1 g - T`
adding we get ` (m_1 + m_2) a = (m_1 - m_2) g `
putting the values, we get `m_1/m_2 = 9/7 `
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