The position of an particle is given by `x=6t+2t^(3)`. Find out whether is motion is uniform or non - uniform.

The position of a particle is given by r=2.00t hati-1.00t^(2)hatj+3.00hatk where t is in seconds and the coefficients have the proper unit for r to be in metres. Find the velocity and acceleration of a particle then what is the magnitude and direction of velocity of the particle at t = 2 s?

The position of a particle is given by r=3.0thati-2.0t^(2)hatj+4.0hatkm where t is in seconds and the coefficients have proper units for r to be in metres . (a) Find the v and a of the particle ? (b) What is the magnitude and direction of velocity of the particle at t=2.0s ?

When a particle is in uniform motion it does not have

The law of linear motion of a particle is given by s=1/3t^(3)-16t , the acceleration at the time when the velocity vanishes is

If position of a particle at instant t is given by x=3t^(2) , find the velocity and acceleration of the particle.

The position x of a particle with respect to time t along x is in given by x =9t^2-t^3 where x is in meters and t in second. What will be the position of this particle when it achieves maximum speed along the "+x directions?

If the position vector of the particle is given by vecr=3hatt^(2)hati+5thatj+4hatk , Find the (a) The velocity of the particle at t=3s (b) Speed of the particle at t= 3s (c) Acceleration of the particle at time t=3s

The acceleration of a particle in ms^(-1) is given by a=3t^(2)+2t+2 where timer is in second If the particle starts with a velocity v=2ms^(-1) at t=0 then find the velocity at the end of 2s.