Two particles having charges `Q_(1) and Q_(2)` , when kept at a certain distance, exert a force F on each other. If the distance between the two particles is reduced to half and the charge on each particle is doubled. Find the force between the particles.

Explanation

`F = (1)/(4 pi epsilon_(0)) (Q_(1)Q_(2))/(r^(2))`
If the distance is educed by half and two particles of charges are doubled.
F. = `(1)/(4pi epsilon_(0)) (2Q_(1)2Q_(2))/((r//2)^(2)) = (1)/(4pi epsilon_(0)) (4Q_(1)Q_(2))/((r^(2)//4)^(2))`
`F. = (1)/(4pi epsilon_(0)) (16(Q_(1)Q_(2)))/(r^(2)) = 16 [ (1)/(4pi epsilon_(0)) (Q_(1)Q_(2))/(r^(2))]`
F. = 16 F