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Two charges are placed in vacuum at a di...

Two charges are placed in vacuum at a distance d apart. The force between them is F. if a medium of dielectric constant 2 is introduced between them, the force will now be

Text Solution

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Force between the charges (vacuum)
`F = (1)/(4pi epsilon_(0)) (q_(1)q_(2))/(d^(2))`
Force between the charges (medium)
`F. = (1)/(4pi epsilon) (q_(1)q_(2))/(d^(2))" " [epsilon = epsilon_(0) epsilon_(r)]`
F. ` = (1)/(4pi epsilon_(0)epsilon_(r)) (q_(1)q_(2))/(d^(2)) = (1)/(4pi epsilon_(0)(2)) (q_(1)q_(2))/(d^(2)) = (1)/(1) [ (1)/(4pi epsilon_(0)) (q_(1)q_(2))/(d^(2))]`
F. = `(F)/(2)`
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