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Find the force of attraction between the...

Find the force of attraction between the plates of a parallel plate capacitor.

Text Solution

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Let d be the distance between the plates. Then the capacitor is
C = `(epsilon_(0)A)/(d)`
Energy stored in a capacitor, U = `(q^(2))/(2C) = (q^(2).d^(2))/(2 epsilon_(0)A) `
Energy magnitude of the force is,
`|F| = (dU)/(dx) = (d)/(dx) [ (q^(2) x)/(2 epsilon_(0) A) ] " " [ x = d ]`
= `(q^(2))/(2 epsilon_(0)A) [ (d)/(dx) (x) ] `
F = `(q^(2))/(2 epsilon_(0)A)`
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