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A copper wire of cross-sectional area 0....

A copper wire of cross-sectional area 0.5 `m m^(2)` carries a current of 0.2A. If the free electron density of copper is `8.4xx10^(28)m^(-3)` then compute the drift velocity of free electrons.

Text Solution

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The relation between drift velocity of electrons and current a wire of cross-sectional area A is
`v_(d)=(1)/(n eA)=(0.2)/(8.4xx10^(28)xx1.6xx10^(-19)xx0.5xx10^(-6))`
`v_(d)=0.03xx10^(-3)ms^(-1)`
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