Calculate the equivalent resistance in the following circuit and also find the current `I,I_(1) and I_(2)` in the given circuit.

Explanation

Since the resistances are connected in parallel, therefore, the equivalent resistance in the circuit is
`(1)/(R_(P))=(1)/(R_(1))+(1)/(R_(2))=(1)/(4)+(1)/(6)`
`(1)/(R_(P))=(5)/(12)Omega`
`or R_(P)=(12)/(5)Omega`
The resistors are connected in parallel, the potential (voltage) across each resistor is the same.
`I_(1)=(V)/(R_(1))=(24V)/(6Omega)=6A`
`I_(2)=(V)/(R_(2))=(24)/(6)=4A`
The current I is the total of the currents in the two branches. Then,
`I=I_(1)+I_(2)=6A+4A=10A`