Calculate the equivalent resistance betweeen A and B in the given circuit.

Explanation

Parallel connection
Part 1 `" " (1)/(R_(p_(1)))=(1)/(R_(1))+(1)/(R_(2))`
`(1)/(R_(p_(1)))=(1)/(2)+(1)/(2)=(2)/(2) rArr R_(p_(1))=1Omega`

Part II `" " (1)/(R_(p_(2)))=(1)/(4)+(1)/(4)=(2)/(4) rArr (1)/(R_(p_(2)))=(1)/(2) rArr R_(p_(2))=2Omega`

Part III `" " (1)/(R_(p_(3)))=(1)/(6)+(1)/(6)=(2)/(6) rArr (1)/(R_(p_(3)))=(1)/(3) rArr R_(p_(3))=3Omega`
`R=R_(p_(1))+R_(p_(2))+R_(p_(3)) rArr R=1+2+3R=6Omega`
The circuit became:

Equivalent resistance between A and B is