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Resistance of a material at 10^(@)C and ...

Resistance of a material at `10^(@)C` and `40^(@)C` are `45Omega` and `85Omega` respectively. Find its temperature co-efficient of resistance

Text Solution

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`T_(0)=10^(@)C , T=40^(@)C, R_(0)=45Omega, R=85Omega`
`alpha=(1)/(R_(0))(DeltaR)/(DeltaT)`
`alpha=(1)/(45)((85-45)/(40-10))=(1)/(45)((40)/(30))`
`alpha=0.0296 "per"^(@)C`
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