From the given circuit find the value of I.

Explanation

Applying Kirchoff.s rule to the point P in the circuit, The arrows pointing towards P are positive and away from P are negative.
Therefore, `0.2A-0.4A+0.6A-0.5A+0.7A-I=0`
`1.5A-0.9A-I=0`
`0.6A-I=0`
`I=0.6A`