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In a meter bridge with a standard resist...

In a meter bridge with a standard resistance of `15Omega` in the right gap, the ratio of balancing length is `3:2`. Find the value of the other resistance.

Text Solution

Verified by Experts

`Q=15Omega, l_(1):l_(2)=3:2`
`(l_(1))/(l_(2))=(3)/(2)`
`(P)/(Q)=(l_(1))/(l_(2)) rArr P=Q(l_(1))/(l_(2))`
`P=15(3)/(2)=22.5Omega`
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