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An element hobbyist is building a radio ...

An element hobbyist is building a radio which reequires `150 Omega` in her circuit, but she has only `220Omega, 79 Omega and 92 Omega` resistors available. How can she connect the available resistor to get desired value of resistance ?

Text Solution

Verified by Experts

Required effective resistance `=150Omega`
Given resistors of resistance, `R_(1)=220Omega, R_(2)=79Omega, R_(3)=92Omega`
Parallel combination of `R_(1) and R_(2)`
`(1)/(R_(p))=(1)/(R_(1))+(1)/(R_(2))=(1)/(220)+(1)/(79)=(79+220)/(220xx79)`
`R_(p)=58Omega`

Parallel combination of `R_(p) and R_(3)`
`R_(s)=R_(p)+R_(3)=58+92`
`R_(s)=150Omega`
Parallel combination of `220Omega and 79Omega` in series with `92Omega`
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