A cell of emf 2V and internal resistance 0.1 `Omega` is connected with a resistance of `3.9Omega` . The voltage across the cell terminals will be

Options

A. a) 0.5 V
B. b) 1.9 V
C. c) 1.95 V
D. d) 2 V

Answer

C

Explanation

`V=(ER)/(R+r)=(2xx3.9)/(3.9+0.1)=1.95V`