Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to `81.9 xx 10^(-15) J`. (Given `:` mass of proton is 1836 times that of electron ) .

Explanation

`{:("de-Broglie wavelength of proton,",,m_(p) = 1.67 xx 10^(-27)kg),(lambda = (h)/(sqrt(2 mK)),,K.E = 81.9 xx 10^(-15) J):}`
`= (6.6 xx 10^(-34))/(sqrt(2 xx 1.67 xx 10^(-27) xx 81.9 xx 10^(-15))) =(6.6 xx 10^(-34))/(1.6539 xx 10^(-20)) = 3.99 xx 10^(-14)`
`lambda = 4 xx 10^(-14) m`