An electron is accelerated through a potential difference of 81V. What is the de Broglie wavelength associated with it? To which part of electromagnetic spectrum does this wavelength corresspond ?

Explanation

de-Broglie wavelength of an electron beam accelerated through a potential difference of V volts is
`lambda = (h)/(sqrt(2meV)) = (1.23)/(sqrt(V)) nm`
V = 81 V, so `lambda = (1.23)/(sqrt(81)) xx 10^(-9)m = 0.1366 xx 10^(-9)m`
`lambda = 1.36 Å`
X-ray is the part of electromagnetic spectrum does this wavelength corresponds. X-ray has the wavelengths ranging from about `10^(-8)` to `10^(-12)` m.