An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. Its final velocity will be

Options

A. `sqrt((2eV)/(m))`
B. `sqrt((eV)/(m))`
C. `(eV)/(2m)`
D. `(eV)/(m)`

Answer

A

Explanation

K.E. gained by an electron when accelerated through a potential difference V, `(1)/(2) mv^(2) = eV or v = sqrt((2eV)/(m))`