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The energy of photon of wavelength lambd...

The energy of photon of wavelength `lambda` is

A

`(hc)/(lambda)`

B

`h lambda c`

C

`(lambda)/(hc)`

D

`(h lambda)/(c)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E = h upsilon = (hc)/(lambda)`
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