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The ratio of the energy of a photon with...

The ratio of the energy of a photon with `lambda = 150` nm to that with `lambda = 300` nm is

A

2

B

`(1)/(4)`

C

0.2

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(E_(1))/(E_(2)) = (lambda_(2))/(lambda_(1)) = (300)/(150) = 2`
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