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Momentum of photon of wavelength lambda ...

Momentum of photon of wavelength `lambda` is

A

`(h)/(lambda)`

B

zero

C

`(h lambda)/(c^(2))`

D

`(h lambda)/(c)`

Text Solution

Verified by Experts

The correct Answer is:
A
`p = mc = (mc^(2))/(c) = (h upsilon)/(c)`
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FULL MARKS-DUAL NATURE OF RADIATION AND MATTER-ADDITIONAL QUESTIONS -(MULTIPLE CHOICE QUESTIONS )
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