The momentum of a photon of energy 1 MeV is kg m/s will be

Options

A. `5 xx 10^(-22)`
B. `0.33 xx 10^(6)`
C. `7 xx 10^(-24)`
D. `10^(-22)`

Answer

A

Explanation

`P = (E)/(C) = (1 MeV)/(3 xx 10^(8) ms^(-1)) = (1.6 xx 10^(-13) J)/(3 xx 10^(8) ms^(-1)) = 5.33 xx 10^(-22) "kg ms"^(-1)`