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The wavelength of de-Broglie wave is 3 m...

The wavelength of de-Broglie wave is 3 `mu m`, then its momentum `(h = 6.63 xx 10^(-34) Js)` is

A

`3.315 xx 10^(-28) "kg ms"^(-1)`

B

`2.21 xx 10^(-28) "kg ms"^(-1)`

C

`4.97 xx 10^(-28) "kg ms"^(-1)`

D

`9.9 xx 10^(-28) "kg ms"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`p = (h)/(lambda) = (6.03 xx 10^(-34) Js)/(2 xx 10^(-6) m) prop 3.315 xx 10^(-28) "kg ms"^(-1)`
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