de-Broglie wavelength `lambda` associated with neutrons is related with absolute temperature T as

Options

A. `lambda prop T`
B. `lambda prop (1)/(T)`
C. `lambda prop (1)/(sqrt(T))`
D. `lambda prop T^(2)`

Answer

C

Explanation

`k = (3)/(2) KT`
`lambda = (h)/(sqrt(2 mK)) = (h)/(sqrt(3 m KT)) rArr lambda prop (1)/(sqrt(T))`