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The potential difference between the cathode and the target in a coolidge tube is 120 kV. What can be the minimum wavelength (in `Å`) of the X-rays emitted by this tube ?

A

0.4 `Å`

B

0.3 `Å`

C

0.2 `Å`

D

0.1 `Å`

Text Solution

Verified by Experts

The correct Answer is:
D
`lambda_(min) = (12375)/(V)Å = (12375)/(120 xx 10^(3)) Å = 0.1 Å`
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