Home
Class 12
PHYSICS
A proton and an alpha particle, both ini...

A proton and an alpha particle, both initially at rest, are accelerated so as to have the same kinetic energy. What is the ratio of their de-Broglie wavelength ?

Text Solution

Verified by Experts

de-Broglie wavelength,
`lambda = (h)/(p) = (h)/(sqrt(2 mK))`
i.e. `lambda prop (1)/(sqrt(m)) " "[m_(alpha) = 4 m_(p)]`
`(lambda_(p))/(lambda_(alpha)) = sqrt((m_(alpha))/(m_(p))) = sqrt((4 m_(p))/(m_(p))) = sqrt((4)/(1)) = (2)/(1)`
`lambda_(p) : lambda_(alpha) = 2 : 1`
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE OF RADIATION AND MATTER

    FULL MARKS|Exercise ADDITIONAL QUESTIONS -( LONG ANSWER QUESTIONS )|7 Videos
  • CURRENT ELECTRICITY

    FULL MARKS|Exercise Additional Questions Solved (Numerical Problems)|6 Videos
  • ELECTROSTATICS

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED ( VII. NUMERICAL PROBLEMS )|5 Videos

Similar Questions

Explore conceptually related problems

A proton and a deuteron have the same velocity, what is the ratio of their de Broglie wavelengths ?

A proton and an alpha -particle are accelerated through the same potential difference. The ratio of de-Broglie wavelength of proton to the de-Broglie wavelength of alpha particle will be

A proton and an electron have same kinetic energy. Which one has greater de Broglie wavelength. Justify.

An electron of mass m and photon have same energy E. The ratio of de-Broglie wavelength associated with them is:

An electron of mass m_(e ) and a proton of mass m_(p) are accelerated through the same potential. Then the ratio of their de Broglie wavelengths is