Calculate the average atomic mass of chlorine if no distinction is made between its different isotopes?

Explanation

The element chlorine is a mixture of `75.77 %` of `""_(17)^(35)"CI"` and `24.23 %` of `""_(17)^(37)"CI"`. So the average atomic mass will be
`(75.77)/(100) xx 34.96885u + (24.23)/(100)xx 36.96593u = 35.453u`.
In fact, the chemist uses the average atomic mass or simply called chemical atomic weight(35.453 u for chlorine) of an element. So it must be remember that the atomic mass which is mentioned in the periodic table is basically averaged atomic mass.