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If the nuclear radius of ""^(27)Al is 3....

If the nuclear radius of `""^(27)Al` is 3.6 fermi, the approximate nuclear radius of `""^(64)Cu` is

A

`2.4`

B

`1.2`

C

`4.8`

D

`3.6`

Text Solution

Verified by Experts

The correct Answer is:
C
`(R_(AI))/(R_(Cu)) = (27)^(1/3)/(64)^(1/3) = 3/4`
`R_(Cu) = 4/3 R_(AI) = 4/3 xx 3.6` fermi
`R_(Cu) = 4.8` fermi
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