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The mass of a ""(7)^(3)Li nucleus is 0.0...

The mass of a `""_(7)^(3)Li` nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of `""_(7)^(3)Li` nucleus is nearly

A

46 MeV

B

5.6 MeV

C

3.9 MeV

D

23 MeV

Text Solution

Verified by Experts

The correct Answer is:
B
If `m = 1 u, C = 3 xx 10^(8) ms^(-1)` then, E = 931 MeV
`1 u = 931 MeV`
Binding energy `= 0.42 xx 931`
`= 39.10 MeV`
Binding energy per nucleon = `(B.E)/(A) = (39.10)/(7) = 5.58 = 5.6 MeV`
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