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The energy of the ground state of hydrog...

The energy of the ground state of hydrogen is -13.6eV. The energy of the first excited state is

A

`-27.2` eV

B

`-52.4` eV

C

`-3.4` eV

D

`-6.8` eV

Text Solution

Verified by Experts

The correct Answer is:
C
For the first excited state, n = 2
`therefore E_(2) = (E_(1))/(E_(2)) = (-13.6 eV)/(4) = -3.4 eV`
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