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The total energy of electron in the grou...

The total energy of electron in the ground state of hydrogen atom is `(-13.6 eV)`. The kinetic energy of an electron in the first excited state is

A

`6.8` eV

B

`13.6` eV

C

`1.7` eV

D

`3.4` eV

Text Solution

Verified by Experts

The correct Answer is:
D
Total energy in the first excited state,
`E_(2) = (E_(1))/(E_(2)) = (E_(1))/(E_(2)) = (-13.6)/(4) = -3.4 eV`
` K.E = - E_(2) = 3.4 eV`
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