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What would be the radius of second orbit...

What would be the radius of second orbit of `He^(+)` ions?

A

`1.058 Å`

B

`3.023 Å`

C

`2.068 Å`

D

`4.458 Å`

Text Solution

Verified by Experts

The correct Answer is:
A
`r_(n) = (n^(2))/(Z) r_(1)`
For `He^(+) ion, n = 2, Z = 2`
`therefore r_(2) = (4)/(2)xx0.529 Å = 1.058 Å`
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