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Wavelength of a light emitted from secon...

Wavelength of a light emitted from second orbit to first orbit in a hydrogen atom is

A

`1.215 xx 10^(-7)` m

B

`1.215 xx 10^(-5)`m

C

`1.215 xx 10^(-4)` m

D

`1.215 xx 10^(-3)` m

Text Solution

Verified by Experts

The correct Answer is:
A

`1/(lambda) = R [(1)/(1^(2)) - (1)/(2^(2))] = (3R)/(4)`
`lambda = (4)/(3R) = (4)/(3 xx 1.097 xx 10^(7)) = 1.215 xx 10^(-7)`m
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