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Calculate the range of the variable capa...

Calculate the range of the variable capacitor that is to be used in a tuned-collector oscillator which has a fixed inductance of 150 `p`H.The frequency band is from 500 KHz to 1500KHz.

Text Solution

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Resonant frequency `f_(0) =1/(2pi sqrt(LC))`
On simplifying we get `C = 1/(4pi^(2)f_(0)^(2)L)`
When frequency is equal to 500 kJz
`C = 1/(4 xx 3.14^(2) xx (500 xx 10^(3))^(2) xx 150 xx 10^(-6)) = 676 pF`
When frequency is equal to 1500 kHz
`C = 1/(4 xx 3.14 xx (1500 xx 10^(3))^(2) xx 150 xx 10^(-6)) = 75 pF`
Therefore, the capacitor range is 75 - 676 pF
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