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The wavelenght of a light is 450 nm. How...

The wavelenght of a light is 450 nm. How phase it will differ for a path of 3 mm?

Text Solution

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The wavelenght is `lambda =450 nm =450 xx10^(-9)m`
Path difference is `delta=3 mm =3 xx10^(-3)m`
Relation between phase difference and path difference is `phi=(2pi)(lambda)xxdelta`
Substituting `phi=(2pi)/(450xx10^(-9))xx3 xx 10^(-3)=(pi)/(75)xx10^6`
`phi=(pi)/(75)xx10^6` rad
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