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If `f(theta)=|cos^2thetacosthetasintheta-sinthetacosthetasinthetasin^2thetacosthetasintheta-costheta0|,t h e r ef(pi/3)+f((2pi)/3)+f(pi)+f((4pi)/3)++f((npi)/3)` is equal to `n` (b) `(n(n+1))/2` (c) `n^2+2n` (d) `2n^2-n`

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