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""(92)U^(235) experiences one alpha - de...

`""_(92)U^(235)` experiences one `alpha` - decay and one `beta`- decay. Find number of neutrons in the final daughter nucleus that is formed.

Text Solution

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Let X and Y be the resulting nucleus after the emission of the alpha and beta particles respectively
`""_(92)U^(235) overset(alpha "decay") to ""_(90)X^(231)+ ""_(2)He^(4)`
`""_(90)X^(231) overset(beta "decay") to ""_(91)Y^(231) + ""_(-1)e^(0)`
Number of neutrons = Mass number - Atomic number = 231 -91 = 140
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