A hydraulic system is used to lift a 2000 kg vehicle in an auto garage. If the vehicle sits on a piston of area `0.5 m^(2)` , m, and a force is applied to a piston of area `0.03m^(2)` , what is the minimum force that must be applied to lift the vehicle?
Given: Area covered by the vehicle on the piston `A_(1) = 0.5 m^(2)`
Weight of the vehicle , `F_(1) = 2000 kg xx 9.8 m s^(-2)`
Area on which force `F_(2)` is aplied , `A_(2) = 0.03 m^(2)`

Explanation

`P_(1) = P_(2) , F_(1)/A_(1) = F_(2)/A_(2) " and " F_(2) = F_(1)/A_(1) A_(2) ` ,
` F_(2) = (2000 xx 9.8) (0.03)/(0.5) = 1176 ` N