An object 2 cm high is placed at a distance of 16 cm from a concave mirror which produces a real image 3 cm high. Find the position of the image.

Explanation

Height of object `h_1 =2` cm
Height of real image `h_2 = -3` cm
Magnification `m = (h_2)/(h_1) = (-3)/(2) = -1.5`
We know that, `m = (-v)/(u )`
Here, object distance `u= -16 cm`
Substituting the value, we get
`-1.5 = -(v)/((16)) rArr 1.5 = (v)/( 16) rArr = 16 xx (-1.5) = -24 c`
The position of image is 24 cm in front of the mirror (negative sign indicates that the image is. on the left side of the mirror).