Home
Class 6
MATHS
Find the least number which when divide...

Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Text Solution

AI Generated Solution

To find the least number which, when divided by 6, 15, and 18, leaves a remainder of 5 in each case, we can follow these steps: ### Step 1: Understand the Problem We need to find a number \( N \) such that: - \( N \mod 6 = 5 \) - \( N \mod 15 = 5 \) - \( N \mod 18 = 5 \) ...
Promotional Banner

Topper's Solved these Questions

  • PLAYING WITH NUMBERS

    NCERT|Exercise EXERCISE 3.2|11 Videos

  • PLAYING WITH NUMBERS

    NCERT|Exercise EXERCISE 3.1|4 Videos

  • PLAYING WITH NUMBERS

    NCERT|Exercise EXERCISE 3.5|12 Videos

  • MENSURATION

    NCERT|Exercise EXERCISE 10.2|1 Videos

  • RATIO AND PROPORTION

    NCERT|Exercise SOLVED EXAMPLES|15 Videos

Similar Questions

Explore conceptually related problems

Find the least number which when divided by 16, 18 and 20 leaves a remainder 4 in each case, but is completely divisible by 7.

Find the least number which when divided by 25, 40 and 60, leaves remainder 7 in each case.

Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.

Find the least number which when divided by 16,36 and 40 leaves 5 as remainder in each case.

Find the least number which when dividded by 12, 16, 18, 30 leaves remainder 4 in each case but it is completely divisible by 7 ?

Let x be the least number, which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case but when divided by 9 leaves remainder 0. The sum of digits of x is:

The least number which when divided by 12, 16 and 18 leaves 5 as remainder in each case. Find the number.