Renu purchases two bags of fertiliser of weights 75 kg and 69 kg. Find the maximum value of weight which can measure the weight of the fertiliser exact number of times.

Explanation

To find the maximum value of weight that can measure the weights of the fertiliser (75 kg and 69 kg) an exact number of times, we need to calculate the Highest Common Factor (HCF) of the two weights. Here’s how to do it step by step:

### Step 1: Find the prime factorization of each weight.

- **For 75 kg:**
- Divide 75 by the smallest prime number, which is 3:
- \( 75 ÷ 3 = 25 \)
- Now, factor 25:
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