Home
Class 11
PHYSICS
A bullet fired at an angle of 30^(@) wi...

A bullet fired at an angle of `30^(@)` with the horizontal hits the ground 3 . 0 km away. By adjusting its angle of projection, can one hope to hit a target 5 . 0 km away ? Assume the muzzle speed to be fixed, and neglect air resestance .

Text Solution

Verified by Experts

As Horizontal range `=R=(u^(2) sin 2 theta)/(g) `
`3=(u^(2) sin 2 (30^(@)))/(g)=(u^(2))/(g), (sqrt3)/(2)`
`therefore (u^(2))/(g)=(3xx2)/(sqrt3)=2sqrt3=3.464 km`
As maximum horizontal range `=(u^(2))/(g)=3.464 km`
Therefore , the bullet can never hit the target placed at `5.0 km` away .
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise NCERT FILE (Solved) (NCERT (Exemplar Problems Subjective Questions) Very short nswer type questions)|13 Videos

  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise Higher Order Thinking Skills & Advanced Level|6 Videos

  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise NCERT FILE (Solved) NCERT (Textbook Exercises)|25 Videos

  • MECHANICAL PROPERTIES OF FLUIDS

    MODERN PUBLICATION|Exercise Chapter Practise Test|16 Videos

  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos

Similar Questions

Explore conceptually related problems

A bullet fired at an angle of 30^(@) with the horizontal hits the ground 3 km away. By adjusting the angle of projection, can one hope to hit a target 5 km away ? Assume the muzzle speed to be fixed and neglect air resistance.

A bullet fired at an angle of 30^@ with the horizontal hits the ground 3.0 km away. By adjusting its angle of projection, can one hope to hit a target 5.0 away? Assume the muzzle speed to be fixed and neglect air resistance.

A bullet fired at an angle of 30^(@) with the horizontal hits the ground 3 sqrt 3 km away. Can wr hit a target at a distance of 6 sqrt 2km by adjustion its angle of projection?

A bullet is fired at an angle of 15^@ with the horizontal and hits the ground 6 km away. Is it possible to hit a target 10 km away by adjusting the angle of projection assuming the initial speed to be the same ?

A bullet is fired at an angle of 15^(@) with the horizontal and it hits the ground 3 km away. Can we hit a target at a distance of 7 km by just adjusting its angle of projection ?

A bullet fired at an angle of 60^@ with the vertical hits the ground at a distance of 2 km. Calculate the distance at which the bullet will hit the ground when fired at an angle of 45^@ ,assuming the speed to be the same.

Points A and C are on the horizontal ground and A and B are in same vertical plane at a distance of 1500 m . Simultaneously bullets are fired from A,Bll and C and they collide at O . The bullets at B is fired at an angle of 30^(@) with horizontal towards the ground iat velocity 100 m//s . the bullet at C is projected vertically upwards at velocity of 100 m//s . the bullet projected from A reaches its maximum height at O . Find the elevation angle angletheta=angleOAC :