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A body is projected at angle of 45^(@) t...

A body is projected at angle of `45^(@)` to the horizontal . What is its velocity at the highest point ?

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To find the velocity of a body projected at an angle of \(45^\circ\) to the horizontal at its highest point, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Components of Velocity**: When a body is projected at an angle, its initial velocity \(u\) can be broken down into two components: - Horizontal component: \(u_x = u \cos(45^\circ)\) - Vertical component: \(u_y = u \sin(45^\circ)\) ...
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MODERN PUBLICATION-MOTION IN A PLANE -Revision Exercises (very Short Answer Questions)
  1. What will be the value of vecA. (vec(B)(C)) if vecA, vecB, vecC are pe...

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  2. Under what condition, the three vectors (i) cannot giv zero resultant ...

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  3. What is a projectile ? Give its examples. Show that the path of projec...

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  4. TRAJECTORY OF HORIZONTAL PROJECTILE

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  5. Define time of flight for a projectile .

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  6. The horizontal range for projectile is given by

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  7. What do you mean by maximum height attained by a projectile ?

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  8. What do you mean by angular displacement ? Is it a scalar or vector ?

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  9. What is angular velocity ? What is its unit?

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  10. What is centriprtal acceleration ? In which direction it acts ?

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  11. Can there be a motion in two dimensions with an acceleration only in o...

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  12. A ball is thrown straight up. What is its velocity and acceleration at...

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  13. CENTRIFUGAL FORCE

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  14. At which angle the maximum height attained by aprojectile is maximum ?

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  15. What will be the ratio of time of flights of two projectiles fired at...

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  16. Two bodies of masses 4 kg and 6 kg are thrown with the same velocity i...

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  17. What is the angle between velocity vector and acceleration vector in u...

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  18. A projectile is fired from horizontal at an angle theta . What are the...

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  19. A body is projected at angle of 45^(@) to the horizontal . What is its...

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  20. A body is thrown with a kinetic energy of 5 j. What will be its kineti...

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