A vector is given by `vecV=(8.0hati+2.0hatj)m//s` . What will be the unit vector perpendicular to `vecV`?

Explanation

To find a unit vector that is perpendicular to the given vector \(\vec{V} = (8.0 \hat{i} + 2.0 \hat{j}) \, \text{m/s}\), we can follow these steps:

### Step 1: Understand the given vector
The vector \(\vec{V}\) has components along the x-axis and y-axis. Specifically, it has \(8.0 \hat{i}\) in the x-direction and \(2.0 \hat{j}\) in the y-direction.

### Step 2: Identify the conditions for perpendicularity
Two vectors are perpendicular if their dot product is zero. Therefore, if we have another vector \(\vec{A} = x \hat{i} + y \hat{j}\), we need to find \(x\) and \(y\) such that:
\[
...