A circular loop of radius R, carries current. At what distance from the centre of the loop along the axis, the magnetic field intensity becomes half of its magnetic field intensity at the centre. Given: `root(3)(4) = 1.5874 & sqrt(0.5874) = 0.7664`.

Explanation

To solve the problem, we need to find the distance \( x \) from the center of a circular loop along its axis where the magnetic field intensity becomes half of its value at the center.

### Step-by-step Solution:

1. **Magnetic Field at the Center of the Loop**:
The magnetic field intensity \( B \) at the center of a circular loop of radius \( R \) carrying a current \( I \) is given by the formula:
\[
B = \frac{\mu_0 I}{2R}
...