A pure semiconductor of volume `3.5 xx10^(-7) m^(3)` contains `5xx10^(20)` conduction electrons per `m^(3)` determine the number of holes present in it

Explanation

To determine the number of holes present in a pure semiconductor, we need to first calculate the total number of conduction electrons in the given volume and then use the properties of pure semiconductors to find the number of holes.

### Step-by-Step Solution:

1. **Identify the given data:**
- Volume of the semiconductor (V) = \(3.5 \times 10^{-7} \, \text{m}^3\)
- Number of conduction electrons per cubic meter (n) = \(5 \times 10^{20} \, \text{electrons/m}^3\)

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