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A pure semiconductor of volume 3.5 xx10...

A pure semiconductor of volume `3.5 xx10^(-7) m^(3)` contains `5xx10^(20)` conduction electrons per `m^(3)` determine the number of holes present in it

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To determine the number of holes present in a pure semiconductor, we need to first calculate the total number of conduction electrons in the given volume and then use the properties of pure semiconductors to find the number of holes. ### Step-by-Step Solution: 1. **Identify the given data:** - Volume of the semiconductor (V) = \(3.5 \times 10^{-7} \, \text{m}^3\) - Number of conduction electrons per cubic meter (n) = \(5 \times 10^{20} \, \text{electrons/m}^3\) ...
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Knowledge Check

  • A piece of pure semiconductor of silicn of size 1cm xx 1 cm xx 1 mm is having 5 xx 10^(28) number of atoms per cubic metre. It is doped simultaneously with 5 xx 10^(22) atoms per m^(3) of aresenic adn 5 xx 10^(20) per m^(3) atoms of indium. The number density of intrisic current carrier (electrons adn holes) in the pure silicon semiconductor is 1.5 xx 10^(16) m^(-3) . Mobility of electron is 3800 cm^(2) V^(-)S^(-1) The number of holes in this semiconductor are

    A
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    B
    `4.54xx10^(13)`
    C
    `4.54xx10^(9)`
    D
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  • A piece of pure semiconductor of silicn of size 1cm xx 1 cm xx 1 mm is having 5 xx 10^(28) number of atoms per cubic metre. It is doped simultaneously with 5 xx 10^(22) atoms per m^(3) of aresenic adn 5 xx 10^(20) per m^(3) atoms of indium. The number density of intrisic current carrier (electrons adn holes) in the pure silicon semiconductor is 1.5 xx 10^(16) m^(-3) . Mobility of electron is 3800 cm^(2) V^(-)S^(-1) The number of electrons in this semiconductor are

    A
    `5.0xx10^(15)`
    B
    `4.95xx10^(15)`
    C
    `4.95xx10^(22)`
    D
    `25xx10^(22)`

  • A metal wire of cross-sectional area 1m m^(2) contains 5xx10^(22) electrons per cm^(3) . If the electrons move along the wire with average drift velocity 1m m//s , then the current in the wire is ( e=1.6xx10^(-19)C )

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    8A
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    2A
    D
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