In pure silicon semiconductor having same electron and hole concentration of `1.5 xx 10^(16)` the hole density is increased to 1.5 times on doping calculate the electron density in silicon after doping

Explanation

To solve the problem step by step, we will use the principle of charge neutrality in semiconductors, which states that the product of the electron density (n) and hole density (p) is equal to the square of the intrinsic carrier concentration (Ni) at thermal equilibrium.

### Step-by-Step Solution:

1. **Identify Initial Conditions:**
- The initial electron concentration (n_i) = \(1.5 \times 10^{16} \, \text{m}^{-3}\)
- The initial hole concentration (p_i) = \(1.5 \times 10^{16} \, \text{m}^{-3}\)

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