A type semiconductor sample has electron and hole concentration of `1.6 xx 10^(19)` the electron and hole mobility in the sample is `1.2 m^(2) v^(-1) s^(-1)` and 0.001 `m^(2)v^(-1) s^(-1)` respectively calculate the value of resistivity of the sample

Explanation

To calculate the resistivity of the semiconductor sample, we can follow these steps:

### Step 1: Understand the given parameters
We have the following values:
- Electron concentration, \( n = 1.6 \times 10^{19} \, \text{m}^{-3} \)
- Hole concentration, \( p = 1.6 \times 10^{19} \, \text{m}^{-3} \)
- Electron mobility, \( \mu_e = 1.2 \, \text{m}^2/\text{V}\cdot\text{s} \)
- Hole mobility, \( \mu_h = 0.001 \, \text{m}^2/\text{V}\cdot\text{s} \)
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